Using difference of two squares procedure, this becomes How will you simplify this expression (x+y)^2-z^2 / (x+z)^2-y^2 to get x+y-z / x-y+z ? Please explain step by step, and especially what to do with the denominator?

Solve this using the differnce of two square procedure. Viz. a^2 - b^2 = (a + b)(a - b)

You have: {(x+y)^2-z^2} / {(x+z)^2-y^2 }

Numerator: {(x+y)^2-z^2}

Using difference of two squares procedure, we get {(x+y)^2-z^2} = {x + y + z}{x + y - z}

Denominator: {(x+z)^2-y^2}

Using difference of two squares procedure, we get {(x+z)^2-y^2} = {x + z + y}{x + z - y} = {x + y + z}{x - y + z}

Now, dividing numerator by denomiator, we get,

{x + y + z}{x + y - z} / {x + y + z}{x - y + z} = {x + y - z} / {x - y + z}

**Answer: {x + y - z} / {x - y + z}**