Help, worded geometry

Help. How would I be able to solve this step by step I need just one example to work off for other questions. Q:the perimeter of a rectangle is 52 inches. If the length is 10 inches less than twice the width, find its dimensions. P=2L+2w
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1 Answer

Width = W

Twice the width = 2W

10 inches less than twice the width = 2W - 10

Length = L = 2W - 10

Perimeter = 2L + 2W = 52

2L + 2W = 52

2(2W - 10) + 2W = 52

4W - 20 + 2W = 52

6W - 20 = 52

6W = 72

W = 12

L = 2W - 10

L = 2(12) - 10

L = 24 - 10

L = 14

Answer:  The length is 14 inches and the width is 12 inches.
by Level 13 User (103k points)

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