In the figure at the right, △ABC ~ △ADE. 
( The picture and dimensions of the triangle is here: http://i44.tinypic.com/fkoeup.jpg )

a. Substitute values from the diagram into the following proportion: AD/AB = DE/BC
(Hint : AB = AD + DB).

b. Solve the proportion for x.

c. Find the length of AB.

d. What is the area of △ABC?

Thanks in advanced!

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1 Answer

Please help me with a geometry/algebra question; homework due in an hour.

In the figure at the right, △ABC ~ △ADE. 
( The picture and dimensions of the triangle is here: image )

a. Substitute values from the diagram into the following proportion: AD/AB = DE/BC
(Hint : AB = AD + DB).

AD/AB = DE/BC

8/(8+x) = 5/7

b. Solve the proportion for x.

8/(8+x) = 5/7

8(7) = 5(8 + x)

56 = 40 + 8x

8x = 56 - 40

x = 16/5 ≈ 3.2  ins

c. Find the length of AB.

AB= AD + DB                                                                                                                      AB = 8 + x                                                                                                                            AB = 8 + 3.2

AB = 11.2  ins                                                          

                                                                                                                                                                                                                                                                   d. What is the area of △ABC?

Area of Triangle = ½ Base x Hieght

Area of Triangle = ½(11.2 x 7)

Ara of Triangle = 39.2 ins²



Thanks in advanced!

 

by Level 3 User (2.7k points)

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