Find the length of the perpendicular drawn from the origin to the plane 2x - 3y + 6z + 21=0 solution

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1 Answer

The origin is (0,0,0) so plug this into the equation of the plane: 21.

Now we divide by the magnitude of the normal vector (perpendicular to the plane): √(4+9+36)=√49=7.

The distance is 21/7=3 units. (Normal vector is <2,-3,6>)

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