tangent=dy/dx, weer y=x^0.5
so dy/dx=+0.5*x^-0.5
equashun 2...2x+3y=5, become 3y=-2x+5, or y=(-2/3)x+(5/3)
so it hav slope=-2/3
perpendikular tu -2/3 be +3/2=1.5,
so yu want 0.5*x^-0.5=1.5....0.5x^-0.5=2...or x^-0.5=4
multipli both sides bi x^+0.5...x^(0.5-0.5)=4*x^0.5....or x^0=4*sqrt(x)
become 1=4*sqrt(x)....or sqrt(x)=1/4....
square both sides & yu get x=(1/4)^2....1/16....0.0625