find the equation of tangent line to the graph of y=sqr(x) which is penpendicular to the line 2x+3y=5
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Solve for X by Graphing | TI-83 Plu...
Solve for X by Graphing | TI-83 Plus and TI-84 Plus graphing calculators
tangent=dy/dx, weer y=x^0.5

so dy/dx=+0.5*x^-0.5

equashun 2...2x+3y=5, become 3y=-2x+5, or y=(-2/3)x+(5/3)

so it hav slope=-2/3

perpendikular tu -2/3 be +3/2=1.5,

so yu want 0.5*x^-0.5=1.5....0.5x^-0.5=2...or x^-0.5=4

multipli both sides bi x^+0.5...x^(0.5-0.5)=4*x^0.5....or x^0=4*sqrt(x)

become 1=4*sqrt(x)....or sqrt(x)=1/4....

square both sides & yu get x=(1/4)^2....1/16....0.0625

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