f(x)=4x+8√x; f'(x)=4+4/√x; f'(25)=4+4/5=4.8.
This is the slope at x=25, so the tangent line has the general equation g(x)=4.8x+a where a is a constant.
But g(x) has to pass through (25,140): 140=4.8*25+a; a=140-120=20.
The equation of the tangent line is g(x)=4.8x+20.