Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the zeros 2i and -3+√5
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Complex zeroes always come in pairs so another zero is -2i, which, together with 2i, creates the quadratic:

(x+2i)(x-2i)=x2+4.

Similarly, the irrational zero also has a counterpart -3-√5.

The quadratic is (x+3+√5)(x+3-√5)=x2+6x+9-5=x2+6x+4.

The quartic is;

f(x)=(x2+4)(x2+6x+4)=x4+6x3+4x2+4x2+24x+16=x4+6x3+8x2+24x+16.

by Top Rated User (1.2m points)

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