Find an nth degree polynomial function with real coefficients satisfying the given conditions.

n = 3; 2 and -2 + 3i are zeros; leading coefficient is 1

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The third (complex) root is -2-3i.

The polynomial is (x-2)(x+2+3i)(x+2-3i)=(x-2)(x²+4x+4+9)=(x-2)(x²+4x+13)


   -2x²    -8x-26=x³+2x²+5x-26

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