Find an nth degree polynomial function with real coefficients satisfying the given conditions.

n = 3; 2 and -2 + 3i are zeros; leading coefficient is 1

in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Solve for X by Graphing | TI-83 Plu...
Solve for X by Graphing | TI-83 Plus and TI-84 Plus graphing calculators

The third (complex) root is -2-3i.

The polynomial is (x-2)(x+2+3i)(x+2-3i)=(x-2)(x²+4x+4+9)=(x-2)(x²+4x+13)


   -2x²    -8x-26=x³+2x²+5x-26

by Top Rated User (1.0m points)

Related questions

Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,138 questions
97,020 answers
24,439 users