Finding a polynomial function with the given conditions
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Complex zeroes must be in pairs so zero 1+i must be matched with 1-i. These two zeroes create a quadratic: (x-1)²+1=x²-2x+2 (because (x-1-i)(x-1+i)=(x-1)²+1).

So the polynomial is a(x+3)(x²-2x+2)=a(x³+x²-4x+6) where a is a constant.

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