find the age in the following case .

Five years ago ,a man was seven times as old as his son . Five years hence,the father will be three  times as old as his son.Find their present age .
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1 Answer

F=father's age, S=son's age.

F-5=7(S-5), F+5=3(S+5),

F-5=7S-35, so F=7S-30, and:

7S-30+5=3S+15,

4S=40, S=10 so F=70-30=40.

Father is 40 years old, son is 10 years old.
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