Please show me the steps to solve 8y^2-2

Question

Help me solve 8y^2-2

                        12n^2-48

                        3a^3+6a^2+3a

                       4rs^2-4rs+r

                       m^4-256

                       81-t^4

                       9x^2+13x+4

                       x^3+10x+16

                       16y^4+48y^3+36y^2

                       36c^4-48c^3+16c^2

                       y^8-81

                       32^4-2

                       25-20p+4p^2

                       9+24a+16a^2

                       (4x-3)^2-y^2

Answer 1

1. 8y^2-2=2(4y²-1)=2(2y-1)(2y+1)
2. 12n^2-48=12(n²-4)=12(n-2)(n+2)
3.  3a^3+6a^2+3a=3a(a²+2a+1)=3a(a+1)²
4. 4rs^2-4rs+r=r(4s²-4s+1)=r(2s-1)²
5. m^4-256=(m²-16)(m²+16)=(m-4)(m+4)(m²+16)
6. 81-t^4=(9-t²)(9+t²)=(3-t)(3+t)(9+t²)
7. 9x^2+13x+4=9x²+9x+4x+4=9x(x+1)+4(x+1)=(9x+4)(x+1)
8. x^3+10x+16 (?) x^2+10x+16=x²+8x+2x+16=x(x+8)+2(x+8)=(x+2)(x+8)
9. 16y^4+48y^3+36y^2=4y²(4y²+12y+9)=4y²(2y+3)² or (2y(2y+3))²
10.  36c^4-48c^3+16c^2=4c²(3c-2)² or (2c(3c-2))²
11.   y^8-81=(y⁴-9)(y⁴+9)=(y²-3)(y²+3)(y⁴+9) or (y-√3)(y+√3)(y²+3)(y⁴+9)
12.   32^4-2=2(16x⁴-1)=2(4x²-1)(4x²+1)=2(2x-1)(2x+1)(4x²+1)
13.   25-20p+4p^2=(5-2p)²
14.   9+24a+16a^2=(3+4a)²
15.   (4x-3)^2-y^2=(4x-3-y)(4x-3+y)