Could you please show me the steps to solve: log3^(x+2)=log4^(x-1)

This is a problem in solving an equation using logarithms. could you please show me step by step how it is done?
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1 Answer

log[3^(x+2)] =log[4^(x-1)]

(x+2)*log(3) =(x-1)*log(4)

me assume base=10...

0.477121254(x+2)=0.602059991(x-1)

0.477...x -0.602x=-2*0.477 -0.602...

-0.124938737x=-0.954242509 -0.602059991   =-1.5563025

x=1.5563025/0.124938737

x=+12.456525
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