How would you solve the equation 4^3X=8^X+1 by taking the logarithm of each side?

Instead of solving it by equating exponents, how would you solve it by taking the logarithm of each side?
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1 Answer

3Xlog4=(X+1)log8. Logs are to base 2: 6X=3X+3, so 3X=3 and X=1.
by Top Rated User (1.2m points)

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