how do you rationalize 11 over the square root of 7 minus the square root of 3

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????????????????? 11 / [root(7) - root(3)] ??????????????? . . . multipli top & bottom bi [root(7) + root(3)]. . . . 11*[root(7) + root(3)] / (7-3) . . . . =(11/4)*[root(7) +root(3)]
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