how do you solve logarithms with like bases? 64*4^(3-3n)=4^3

Question

This is a problem i have been working on for two days.  The problem contains like bases, how do i solve?

Answer 1

64 = 4^3

So you have 4^3*4^(3-3n)=4^3.

So divide by the 4^3 and you get 4^(3-3n) = 1

log base 4 on both sides, and you get

3-3n = log(b=4)(1)

log of 1 is always zero.

3n = 3

n = 1

Answer 2

64(4^3-3n)=64      divide both sides by 64 -->

4^(3-3n)=1             take the ln of both sides -->

(3-3n)ln4 = 0         divide both sides by ln4 -->

3-3n=0                    solve for n -->

n=1