2x^4+10x+8=0 solve for (real or imaginary)zeros

solve for (real or imaginary) zeros using quadratic formula
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2x4+10x+8=0, x4+5x+4=0 can't be solved using the quadratic formula, but 2x4+10x2+8=0 can:

 x4+5x2+4=0=(x2+4)(x2+1)=(x+2i)(x-2i)(x+i)(x-i).

Therefore x=-2i, 2i, -i, or i.

by Top Rated User (1.2m points)

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