find all the real zeros for -3(x-2)^3 +24

Finding the real zeros
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1 Answer

-3(x-2)^3 + 24 = 0

(x-2)^3 - 8 = 0

(x-2)^3 = 8

x-2 = 2

x = 4
by Level 13 User (103k points)

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