find all of the zeros of the function

q(x) = x4 - 8x3 + 22x2 - 8x - 39
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1 Answer

x^4-8x^3+22x^2-8x-39=(x+1)(x-3)(x^2-6x+13)=0

x=-1; 3; 3+2i; 3-2i
by Level 8 User (35.3k points)

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