how to find the zeros in this function x^3-4x^2+9x-36

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1 Answer

x3-4x2+9x-36=x2(x-4)+9(x-4)=(x2+9)(x-4), so the zeroes are 4, 3i, -3i.

(x2+9 has complex factors (x-3i)(x+3i)=x2+9.)

by Top Rated User (1.2m points)

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