how do you find the zeros of the function Q(x)=-2.22x^3 +7.413x^2 - 5.8x
Set Q(x) = 0, then
-2.22x^3 + 7.413x^2 - 5.8x = 0
x(2.22x^2 - 7.413x + 5.8) = 0
x(x - m)(x - n) = 0
The three roots are x = 0, x = m, x = n
where m and n are the roots of the quadratic expression, 2.22x^2 - 7.413x + 5.8
which you can solve using the quadratic formula, x = (-b +/- sqrt(b^2 - 4ac) / (2a)
where a = 2.22, b = -7.413, c = 5.8