How to find and graph the real-number solutions for 12n7+2n5=30n3?

Subject: Polynomial Factoring

              Polynomial Graphs: End Behavior
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1 Answer

12n^7+2n^5=30n^3

12n^7+2n^5-30n^3=0

2n^3(6n^4+n^-15)=0

2n^3(2n^2-3)(3n^2+5)=0

2n^3=0 and 2n^2-3=0 and 3n^2+5=0

n=0; n=+ - V(3/2)
by Level 8 User (35.3k points)

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