f'(x) if f(x)=(x²+3)secx

f'(x) if f(x)=(x²+3)secx
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1 Answer

f(x)=(x2+3)sec(x).

Let u=x2+3, then du/dx=2x; v=sec(x), dv/dx=sec(x)tan(x).

f(x)=uv, f'(x)=udv/dx+vdu/dx=(x2+3)sec(x)tan(x)+2xsec(x).

f'(x)=sec(x)((x2+3)tan(x)+2x).

by Top Rated User (1.2m points)

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