Finding the x and y intercept of F(x)=x²+3x-2
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The y intercept is F(x) when x=0, i.e., F(0), so y intercept is -2.

The x intercept is when F(x)=0=x^2+3x-2. x^2+3x=2; x^2+3x+9/4=2+9/4; (x+3/2)^2=17/4,

Take square root of each side: x+3/2=±√17/2=±2.06155 approx, so x=-1.5±2.06155.

Two x intercepts: 0.56155 and -3.56155. (x=-1.5 which lies halfway between the intercepts is the axis of symmetry.)
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