ow can u rewrite these logarithmic equations an equivalent exponent equation or the other way around m=loga x is equivalent to am=x1. log3 5=y,2. loga 7=-2then solvelog2x=-3,logx9=1/2

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  1. log₃5=y, 5=3^y. (y=1.465 approx)
  2. 7=a^-2. (7=1/a², a²=1/7, a=1/√7=√7/7=0.378 approx.)

log₂(x)=-3, x=2^-3=1/2³=⅛.

log[x]9=½, 9=x^½, 81=x, x=81.

by Top Rated User (680k points)

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