GIVEN : triangle ABF is congruent to triangle EDF ;CF is angle bisector of < DFB

PROVE:  triangle BCF is congruent to triangle DCF
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1 Answer

In Δs BCF and DCF:

CF is a common side;

∠CFB and ∠BFC are equal measure because CF bisects ∠BFD;

BF=FD (side lengths of congruent triangles ABF and DEF).

Therefore Δs BCF and DCF are congruent (two sides. and the included angle).

by Top Rated User (1.2m points)

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