find 93/3 using repeated subtraction

Question

need to use repeated subtraction or partial quotients

Answer 1

93 can be split into 90 and 3, so we use 30=3 times 10 to find the number in the tens position.

93-30=63, 63-30=33, 33-30=3, so we subtracted 30 3 times, therefore 3 goes in the tens position.

We now use the remainder 3, and we can subtract 3 only once 3-3=0, so 1 goes in the ones position.

The result is 31. So 93/3=31.