f(x)=

−31x+6

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1 Answer

Let y=f(x)=31x+6, then 31x=y-6 and x=y/31-6/31.

Let x=g(y)=y/31-6/31, so g(x)=f-1(x)=x/31-6/31 in the required standard form (m=1/31 and b=-6/31).

We need to prove this to be the inverse function f(f-1(x))=f-1(f(x))=x.

Let's prove it:

f(f-1(x))=31f-1(x)+6=31(x/31-6/31)+6=x-6+6=x✔️

f-1(f(x))=f(x)/31-6/31=(31x+6)/31-6/31=x+6/31-6/31=x✔️

by Top Rated User (1.2m points)

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