Evaluate the function ( in more info box ) when x is 3 , -3 , 0

Question

h(x)= {x+3 if x< -2 }

           x^2 if -2 <x<1

            -x+2 if x>1

All of those are in the same bracket by the way

Answer 1

h(3)=-x+2=-3+2=-1

h(-3)=x+3=-2+3=0

h(0)=x²=0