and no 2 friends get the same # of coins. What is the largest number of friends Sam could give coins to?

NEED ANSWER BY TONIGHT PLEASE! AND HOW GOT ANSWER

is it 19 btw i got that...
in Word Problem Answers by Level 1 User (160 points)

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1 Answer

The total # of coins you give out is 1 + 2 + 3 + 4 + 5 + and so on

The sum of 1 + 2 + 3 + 4 + .  . +n is n*(n+1)/2

You want that total to be less than or equal to 200

n*(n+1)/2 <= 200

multiply both sides by 2

n*(n+1) <= 400

combine on the left

n^2 +n <= 400

subtract 400 from both sides

n^2 +n -400 <= 0

quadratic formula: if ax^2 +bx +c = 0 then x = ( -b +- sqrt((b^2)-4ac) ) / 2a

( -1 +- sqrt((1^2) -4(1)(-400)) ) / 2(1)

( -1 +- sqrt(1+1600) ) / 2

(-1 +- sqrt(1601) ) / 2

n has to be posive so we use the + of the +- above

(-1 + sqrt(1601) ) /2

(-1 + 40.0125) / 2

39.0125 / 2

19.5062

You can give coins to 19 friends, but you don't have enough coins for a 20th friend.

Answer:  19
by Level 13 User (103k points)

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