The height h of ∆SUR with base SR, b=8cm gives an area of ½bh=24 cm².

Therefore h=24/4=6cm. The areas of the parallelograms PTRS and QURS are the same because their heights are also the same and are equal to h, the height of the triangle SUR. The slant lengths are irrelevant. The area of a parallelogram is bh =8×6=48 cm². Note also that parallelogram QURS has twice the area of ∆SUR because the diagonal US splits the parallelogram into two congruent triangles (SUR and QUS). So the area of PTRS=48 cm². Two parallelograms between the same parallel lines and sharing a common base have the same area.