Given 3<a<4, 4<b<5 Find: a-b/2a

Given 3<a<4, 4<b<5 Find: a-b/2a
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(a-b)/2a=½-b/2a; 6<2a<8. If we take the limits of (2a,b) we get (6,4), (6,5), (8,4), (8,5)

For each of these, calculate ½-b/2a=-⅙, -⅓, 0, -⅛. The smallest of these is -⅓ and the largest is 0, so -⅓<(a-b)/2a<0.

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