Question

Find the value of [(1+2a)/a^3]+[(1+3B)/B^3]. a and B are the roots of 2x^2-6x+3=0 Please give me the ans STEP BY STEP. THANKS

Answer 1

2x^2-6x+3=0

quadratik equashun giv roots=

2.366025404 & 0.633974596

-b/2a=1.5, b^2-4ac=12, sqrt(12)=3.464101615

wich won???? maebee let 0.6339...=a & 2.366...=b

then 1+2a=1+1.267949192=2.267949192

a^3=0.25480947135679...1/a^3=3.924500900636459

(1+2a)/a^3=3.9245...*2.267949192=8.90056864660173

Comments

I know how to find the value of x.
But, my question is to find the values of [(1+2a)/a^3]+[(1+3B)/B^3].
I AM NOT FINDING THE VALUE OF X. TKS