how do you solve 512.3852=2*3.14*r^2+2*3.14*r*15.8

512.3852=2*3.14*r^2+2*3.14*r*15.8
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1 Answer

512.3852=2πr2+2πr×15.8 (surface area of a closed cylinder, length 15.8, radius r).

2πr2+31.6πr-512.3852=0 is a quadratic equation.

r=(-31.6π+√((31.6π)2+4099.0816))/(4π),

r=1.5 units approx.

by Top Rated User (1.2m points)

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