Let S and R be the initial amount Sue and Rani had. Peter had 4S initially.
Sue ends up with S+24.50+13.70=S+38.20.
Peter ends up with 4S-24.50.
Rani ends up with R-13.70.
But these three amounts are all the same, so we can equate Sue’s and Peter’s amounts:
4S-24.50=S+38.20,
3S=24.50+38.20=62.70,
S=62.70/3=$20.90.
That’s how much Sue had at the beginning, so she ends up with 20.90+38.20=$59.10.
(We can find out how much Rani had initially, R-13.70=59.10, R=13.70+59.10=$72.80. And Peter had 4S=$83.60.)
A) Sue had $59.10 in the end (so did the others).
B) Together they had 3×59.10=$177.30.
(This is also the amount they had at the beginning:
20.90+72.80+83.60=$177.30.)