If the length of a building is 2 1 2 times the width and each dimension is increased by 5 ft, then the perimeter is 258 ft. Find the dimensions of the original building in ft.

Question

I need help

Answer 1

Let the original width be w, then the length is 5w/2.

If both dimensions are increased by 5, length=5w/2+5, width=w+5.

Perimeter is 2(length+width)=5w+10+2w+10=258 feet.

So 7w+20=258, 7w=238, w=238/7=34 feet. Original length is 34/2×5=85 feet.