How many odd three digit number can be formed using the digits 0,4,5 and 7 if repetition of digits is not allowed?
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The smallest number must begin with 4, because a leading zero would not form a 3-digit number.

So that leaves two out of the remaining digits, 0, 5, 7. Of these 5 and 7 are odd so must occupy the ones place. Therefore, we have 405, 407, 457 and 475 in the range 400-499.

Then we have 507 and 547. Next we start with 7 and we have 705 and 745.

So altogether we have 8 numbers: 405, 407, 457, 475, 507, 547, 705, 747.

by Top Rated User (628k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
82,575 questions
87,129 answers
1,959 comments
3,693 users