Permutations and combinations
asked May 27, 2017 in Other Math Topics by marwazahoorkhan@gmail.com

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The two particular candidates are first removed from the 10. That leaves 8 to form a group of 4 to make up the team of 6 which includes the two particular candidates. The number of ways of choosing 4 from 8 is:

8*7*6*5/4!=70.

answered May 27, 2017 by Rod Top Rated User (537,180 points)

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