there are      two-point problems.

there are      five-point problems.
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Let P2 is the problem that is worth 2 points   and  P5 the problem that is worth 5 points

we will have:  P2 + P5 = 38 (1)   we will also have:  2P2 + 5P5 = 100 (2)

from the (1) we get P2 = 38 - P5  substituting on (2) where P2 = 38 - P5 we get  2(38 - P5) + 5P5 = 100

->> 76 - 2P5 + 5P5 = 100  ->>   3P5 = 100 - 76  ->>  3P5 = 24 ->> P5 = 24/3 = 8  so the 5 points problems

are 8  substituting to (1) where P5 = 8  we get  P2 = 38 - P5 ->> P2 = 38 - 8 = 30  So the 2 points problems

are 30

So we will have 8 * 5 = 40   and. 30 * 2 = 60  so total problems 40 + 60 = 100
by Level 5 User (13.1k points)

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