The ratio of width and length of a rectangular lot is 2:3. What is it's dimensions if it's perimeter is 300m?
in Word Problem Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Perimeter=300=2(L+W) where L and W are length and width.

L+W=150 and W/L=2/3 so W=2L/3. Therefore L+2L/3=150, 5L/3=150, L=3*150/5=90 and W=2*90/3=60.

So length=90m and width=60m.

by Top Rated User (680k points)

Related questions

Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
83,678 questions
88,568 answers
5,801 users