Need to find the length and width of the rectangle
in Geometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

Call length L and width W. 6 ft longer than twice the width is 2W+6. Perimeter is 2L+2W=102. L=2W+6 so we substitute this in the perimeter equation: 4W+12+2W=102, so 6W+12=102, and 6W=90. Therefore W=15 and L is twice this plus 6 feet=36. Check the perimeter: 2*36+2*15=72+30=102. Checks out!

by Top Rated User (716k points)
????????? maebee yu shood sae:

1. leng=2*wide+6,

2. rim-leng=102 ????????


(2*wide+6) +wide=51





Related questions

Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
84,489 questions
89,397 answers
8,069 users