what is the length of a rectangle if the perimeter is 238 and the width is 54
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4 Answers

P = 238 and w = 54

P = l + w + l + w = 2l + 2w

238 = 2l + 2*54

238 - 108 = 2l

2l = 130

l = 130/2

l = 65

238 = 2*65 + 2*54

238 = 130 + 108

238 = 238
by Level 8 User (36.8k points)
2x+2*54=238

x+54=119

x=119-54=65m the length of rectangle
by

Double 54 and then minus it from 238

thats 130

divide that by 2 that means LENGTH IS 65

by Level 9 User (42.1k points)
The perimeter is twice the length plus twice the width. Divide the perimeter by two, and you are dealing with length plus width, so simply subtract the width to get the length.

Perimeter is 238 ft. Half of that is 119 ft.

Subtract the width:   119 ft - 54 ft = 65 ft.

P = 2L + 2W = (2 * 65 ft) + (2 * 54 ft) = 130 ft + 108 ft = 238 ft
by Level 11 User (78.4k points)

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