The length of a rectangle is twice the width, the area is 98yd^2 find the length and width
asked Jan 10, 2012 in Algebra 2 Answers by anonymous

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1 Answer

A = 98

A = l*w and l = 2w

98 = 2w*w

98 = 2w^2

w^2 = 98/2

w^2 = 49

w = sqrt49

w = 7 yd

l = 2w = 2*7 = 14 yd

98 = 14*7

98 = 98

 

 

answered Jan 10, 2012 by jkhenry Level 8 User (36,860 points)

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