find three consecutive even integers such that twice the largest is equal to two more than three times the smallest. Equation, The three integers are ____, ____, and, _____
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2 Answers

Let the three integers be 2n-2, 2n and 2n+2. Twice the largest is 4n+4=6n-6+2.

4n+4=6n-4; 2n=8, so n=4 and the numbers are 6, 8 and 10.
by Top Rated User (774k points)

Let three consecutive are
2x-2,2x,2x+2

As given
4x+4=6x-6+2
2x=8
x=4

So the numbers are
6,8,10

Understand more about Integers

 

by Level 8 User (30.1k points)

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