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1 Answer

solve for:(x^2)(e^-2x)-(x)(e^-2x)=0

You have a common factor of e^(-2x), so your equation simplifies to,

e^(-2x){x^2 - x} = 0

which devolves to,

x^2 - x = 0

or,

x(x - 1) = 0

giving the solutions,

x = 0, x = 1, both of which are valid for the common term e^(-2x)

Answer: x = 0, x = 1

by Level 11 User (81.5k points)

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