problem 6b-3/3b^2-12, which part of the problem are the excluded value, the sets and real numbers

Question

 Please identify the exclude values, set, and the real numbers for this problem, 6b-3/3b^2-12

Comments

ROD, HELP ME ANSWER MY QUESTIONS PLEASE!!! 

Answer 1

Divide top and bottom by 3: (2b-1)/((b-2)(b+2). Excluded values: b=-2 and 2. The variable b can take any other values in the set of real numbers. As b gets larger, the expression approaches 2b/b^2=2/b, so the expression gets closer and closer to zero from a negative and positive direction, and where b is between -2 and 2. The range of the expression is all real numbers.