Can you please gave domain rational expressions  for this problem 6b-3/3b^2-12
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Divide top and bottom by 3: (2b-1)/(b^2-4)=(2b-1)/((b-2)(b+2)). So the domain is b<>2 and b<>-2, that is, b must not equal 2 or -2. Because that would produce division by zero. All other values of b are valid.

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