How to solve 2log24 + 2log6 + 2log1/9

Question

Please kindly help to solve :

Answer 1

??????? log 10 ??????

log10(24)=1.3802112417116132

so 2*log10(24)=2.7604224834232265

log10(6)=0.7781512503836476

2*that=1.5563025007672952

(1/9)=0.1111111111111...

log10(0.1111111...)=-0.9542425094393733

2*that=-1.9084850188787465

Answer 2

How to solve 2log24 + 2log6 + 2log1/9

2log24 + 2log6 + 2log1/9

= 2log(8*3) + 2log(2*3) + 2log(3^(-2))

= 2log(8) + 2log(3) + 2log(2) + 2log(3) - 4log(3)

= 2log(2^3) + 2log(2)

= 6log(2) + 2log(2)

The final answer can be expressed as: 8log(2) = log(2^8) = log(256)