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1 Answer

Assume log base is 10.

log10(x(x-9))=1 is possibly another way of writing the equation.

x2-9x=101=10, x2-9x-10=0=(x-10)(x+1), so x=-1 or 10, but log(x) cannot be evaluated when x<0. So x=10 should be the solution.

log10(x)+log10(x-9)=1+log10(1)=1+0=1 checks out OK.

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