How to solve 2log24 + 2log6 + 2log1/9
2log24 + 2log6 + 2log1/9
= 2log(8*3) + 2log(2*3) + 2log(3^(-2))
= 2log(8) + 2log(3) + 2log(2) + 2log(3) - 4log(3)
= 2log(2^3) + 2log(2)
= 6log(2) + 2log(2)
The final answer can be expressed as: 8log(2) = log(2^8) = log(256)