There are 53 pieces in total, one is 12 feet, 8 feet and 6 feet how many feet was used in total?

A general foreman had 53 pieces of wood, One was 12 feet, 8 feet and 6 feet, how many feet was used in total?
in Word Problem Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The question isn't clearly stated. If there are three different lengths we haven't been given how much of each length was being used. If we call the numbers of each length L, M and S for long, medium and short then we know that L+M+S=53 and the total length used is 12L+8M+6S feet. We can write this as 12L+8M+6(53-L-M)=6L+2M+318 feet. All we need to know is L and M. For example, the average number of each length is 53/3=17.67. If L=M=18 and S=17 then the total length is 8*18+318=144+318=462 feet, or 12*18+8*18+6*17=462 feet.

by Top Rated User (1.2m points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!

Most popular questions within the last 3000 days

  1. 50+50-25X0+2+2= (19)
  2. it takes 10 road workers 5 days to complete a road repair when working 2 hours a day.Working at the same pace,how many days will it take 2 people working 5 hours a day to finish it? (3)
  3. Solve 15 -1(12÷4+1)? (4)
  4. 8:4(5+2) (3)
  5. How can i represent 1/3; 3/3; 7/3; 10/3 and 15/3 on a number line? (1)

Most popular tags

87,516 questions
100,279 answers
2,420 comments
731,954 users